Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-09-04
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Explicit comparison constants for the standard norms on K^n

Example

Let K{R,C} and let x=(x0,,xn1)Kn with n1. Define

x:=maxj<nxj,x2:=(j<nxj2)1/2,x1:=j<nxj.

Then

xx2x1nx2nx.

In particular, the abstract norm-equivalence theorems on the A page can be read with explicit constants on these three standard coordinate norms.

Facts & Assumptions

Given: A field K{R,C}, an integer n1, and a vector xKn.

[L1]

On Rn, the displayed 1, Euclidean, and max formulas are the standard norms of The p-norms xp for rational p1, and x, and every norm on Rn is equivalent to every other (For n1 all norms on Rn are equivalent).

[L2]

On finite-dimensional complex spaces every two norms are equivalent (All norms on a finite-dimensional complex normed space are equivalent).

Verification

technique · direct
1.1

Since every summand xj2 is nonnegative and one of them equals x2, one has x2j<nxj2=x22, hence xx2. Also x22=j<nxj2(j<nxj)2=x12, so x2x1.

L1algebra
2.1

By Cauchy-Schwarz for the vectors (xj)j<n and (1,,1), x1=j<nxj(j<nxj2)1/2(j<n12)1/2=nx2. Also xjx for every j, so x1nx.

step 1.1algebra
3.1

Combining steps 1.1 and 2.1 yields the displayed chain. Thus [L1] and [L2] become concrete on these coordinate norms.

L1L2step 1.1step 2.1

Remarks

  • The constants are sharp in the standard basis: x=(1,,1) makes x1=nx and x1=nx2.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

37 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources