Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedverified 2026-09-23 (gpt-6-sol)
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The finite-dimensional sl2 quotient of a Verma module

Example

For m∈Z≥0,

L(m)=M(m)/U(sl2)fm+1vm

has basis v‾m,fvm‾,…,fmvm‾ and dimension m+1.

Facts & Assumptions

Given: The highest-vector relations of Verma modules, the PBW basis wn=fnvm of The PBW model of a Verma module, the sl2 commutators [h,f]=−2f, [e,f]=h, and the unique simple quotient A Verma module has a unique simple quotient.

Verification

technique · direct
1.1givenalgebra

Write wn=fnvm. Induction from [h,f]=−2f, [e,f]=h, ew0=0, and hw0=mw0 gives hwn=(m−2n)wn and ewn=n(m−n+1)wn−1 for n≥1. In particular ewm+1=0. The tail W=span⁡{wn:n≥m+1} is stable under e,f,h and equals U(sl2)wm+1: it contains that generated submodule by invariance, while every tail vector is fkwm+1. Hence the quotient has the displayed m+1 surviving, distinct-weight PBW vectors.

2.1step 1.1givenalgebra∎

Any nonzero submodule of the quotient contains a nonzero finite combination of its basis vectors. Their h-eigenvalues are distinct, so a finite interpolation polynomial in h extracts some w‾r. Applying er reaches a nonzero multiple of w‾0, because all coefficients k(m−k+1) for 1≤k≤r≤m are nonzero. Applying f then gives every displayed basis vector, so the quotient is simple. The unique-simple-quotient theorem identifies its kernel with J(m) and the quotient with L(m).

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources