Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Equal-variance Gaussian location KL

Example

Let P=N(a,τ2) and Q=N(b,τ2) be real Gaussian laws with τ>0. Their directional divergence is D(P∥Q)=(a−b)22τ2≥0. Equality holds when a=b. This calculation concerns equality of the two laws, not identifiability of arbitrary parameter labels.

Facts & Assumptions

Given: AC, real a,b, and τ>0.

[A1]

The Axiom of Choice: the Gaussian KL lemma and KL nonnegativity theorem assume AC; the lemma derives its countable-choice use from AC.

[F1]

KL divergence between equal-variance Gaussian location laws: for equal-variance Gaussian location laws, D(N(a,τ2)∥N(b,τ2))=(a−b)2/(2τ2).

[F2]

Kullback–Leibler divergence is nonnegative: for probability laws with the published KL direction, divergence is nonnegative and equality means the laws are equal.

Verification

1.1A1F1given

Apply [F1] to the stated laws; its hypotheses are exactly a,b∈R and τ>0, and its AC hypothesis is [A1].

2.1A1F1F2givenalgebra∎

Since (a−b)2≥0 and 2τ2>0, the displayed value is nonnegative and equals zero when a=b. In that case the two Gaussian laws coincide, so the equality clause is consistent with [F2].

Depends on

Used by

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Sources