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A one-dimensional Gaussian prior-to-data conditional interpolation

Example

Assume the Axiom of Choice. Fix a∈R and σmin⁡>0, let Z∼N(0,1), and set σt=1−(1−σmin⁡)t,Xt=σtZ+ta(0≤t≤1). Then Xt∼N(ta,σt2), with density ρt(x∣a)=12π σtexp⁡ ⁣(−(x−ta)22σt2), and a conditional velocity field is ut(x∣a)=a+σmin⁡−1σt(x−ta). For every fixed z∈R, the particle path t↦σtz+ta is a straight line from z to a+σmin⁡z. The endpoint map T(z)=a+σmin⁡z is quadratic-cost optimal from N(0,1) to N(a,σmin⁡2), and its squared transport cost is a2+(1−σmin⁡)2.

Facts & Assumptions

Given: AC, a∈R, σmin⁡>0, and a standard normal random variable Z.

[A1]

The Axiom of Choice is the assertion that every family of nonempty sets has a choice function (The Axiom of Choice); it is required by the Gaussian-law and density suppliers used by [F1].

[F1]

The Gaussian conditional affine map is quadratic-cost optimal: under AC, for d≥1, fixed x1, and σmin⁡>0, the affine conditional Gaussian path has mean tx1, scale 1−(1−σmin⁡)t, the stated Gaussian density and velocity, and a quadratic-cost optimal endpoint map with cost ∥x1∥22+d(1−σmin⁡)2.

Verification

Given: The hypotheses in the Example.

1.1givenA1F1

Apply [F1] with d=1 and x1=a. It gives the law and density of Xt, the field ut(x∣a), and the optimality of T(z)=a+σmin⁡z with cost a2+(1−σmin⁡)2.

2.1givenF1algebra∎

For fixed z, differentiation gives ddt(σtz+ta)=(σmin⁡−1)z+a. Substituting x=σtz+ta into the displayed field yields ut(x∣a)=a+σmin⁡−1σt σtz=a+(σmin⁡−1)z, which is that particle derivative. Since σt>0, its dependence on t is affine and the endpoints are z and a+σmin⁡z.

Diagram

The graph uses a=1 and σmin⁡=1/4. The horizontal coordinate is time t and the vertical coordinate is particle state Xt. The three line segments are the exact paths for starting values z=−1,0,1, evaluated from Xt=(1−3t/4)z+t. The plotted endpoints are the images of those starting values under T(z)=1+z/4; the diagram illustrates the formulas and is not used in the verification.

diagram failed to render:
\begin{tikzpicture}[x=4cm,y=1.2cm]
  \draw[->] (-0.08,0) -- (1.08,0) node[right] {$t$};
  \draw[->] (0,-1.18) -- (0,1.38) node[above] {$X_t$};
  \draw[gray] (1,-0.04) -- (1,0.04) node[below=4pt] {$1$};
  \draw[blue,thick] (0,-1) -- (1,0.75) node[right] {$z=-1$};
  \draw[orange!85!black,thick] (0,0) -- (1,1) node[right] {$z=0$};
  \draw[green!50!black,thick] (0,1) -- (1,1.25) node[right] {$z=1$};
  \fill[blue] (0,-1) circle (1.2pt);
  \fill[orange!85!black] (0,0) circle (1.2pt);
  \fill[green!50!black] (0,1) circle (1.2pt);
\end{tikzpicture}

Source notes

The two sources present the same scalar Gaussian interpolation and its affine velocity. The optimality and cost statement here are inherited from the complete coupling proof in the Gaussian theorem, not from the diagram.

Depends on

Used by

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Sources