Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedverified 2026-09-26 (gpt-6-sol)
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The discrete Heisenberg group has growth degree four

Example

The integral Heisenberg group has homogeneous dimension 4, and therefore its growth function is equivalent to m4.

Facts & Assumptions

Given: The integral Heisenberg group H.

[L1]

The homogeneous dimension is D(H)=∑i⋅rank⁡Z(γi(H)/γi+1(H)) (The homogeneous dimension of a finitely generated nilpotent group).

[L2]

The growth function counts word-metric balls (The growth function of a finitely generated group), and its equivalence class is independent of the finite generating set (Growth type is independent of the finite generating set).

Verification

technique · direct
1.1givenalgebra

Write H=Z3 with multiplication (a,b,c)(a′,b′,c′)=(a+a′, b+b′, c+c′+ab′). A direct commutator calculation gives [(a,b,c),(a′,b′,c′)]=(0,0,ab′−a′b), so γ2(H)=[H,H]={(0,0,c):c∈Z} and γ3(H)=1.

2.1L1step 1.1

The quotient γ1(H)/γ2(H) is generated by the images of (1,0,0) and (0,1,0) and is isomorphic to Z2, while γ2(H)/γ3(H)≅Z. Therefore [L1] gives D(H)=1⋅2+2⋅1=4.

2.2L2step 1.1algebra

Put x=(1,0,0), y=(0,1,0) and z=[x,y]=(0,0,1), using [x,y]=xyx−1y−1. Every element has the unique form xaybzd=(a,b,ab+d), so x,y generate H. A word of length at most m in x±1,y±1 has ∣a∣,∣b∣≤m and ∣c∣≤m2: multiplication by x±1 changes only a, and multiplication by y±1 changes b by ±1 and c by ±a. Thus its ball has at most (2m+1)2(2m2+1) elements.

3.1step 2.2algebra

For an integer d>0, put q=⌊d⌋≥1 and write d=qℓ+r with 0≤r<q. Then ℓ≤q+2 and zd=[xq,yℓ][xr,y], a word of length at most 2q+2ℓ+2r+2≤6q+6. For d<0 invert a word for z−d, and for d=0 use the empty word. Hence, for every integer k≥1, all the distinct elements xaybzd with ∣a∣,∣b∣≤k and ∣d∣≤k2 lie in the ball of radius 8k+6. That ball has at least (2k+1)2(2k2+1) elements.

4.1L2step 2.1step 2.2step 3.1∎

The upper bound in step 2.2 is O(m4) for m≥1. For m≥28, take k=⌊(m−6)/8⌋≥m/16 in step 3.1 to obtain a lower bound by a positive constant times m4. These bounds prove equivalence with m4 for {x,y}, and [L2] transfers that growth type to every finite generating set. Together with step 2.1 this proves the example.

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