Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Homotopy classes as H-zero of a Hom complex

Example

For the two-term identity complex 0→Z→1ZZ→0, the Hom complex from the previous example has ker⁡(∂0)={(a,a):a∈Z},im⁡(∂1)={(a,a):a∈Z}, so H0(Hom⁡‾(C,C))=0. Hence every endomorphism of C is zero in K(Ab).

Facts & Assumptions

Given: The Hom complex of the two-term identity complex with itself.

[L1]

The previous example computes ∂1(m)=(m,m),∂0(a,b)=b−a (The Hom complex of two two-term complexes).

[L2]

Hom in the homotopy category is H0 of the Hom complex (Hom in the homotopy category is zero-degree homology of the Hom complex).

Verification

technique · direct
1.1L1givenalgebra

By [L1], a degree-0 element (a,b) lies in ker⁡(∂0) exactly when b−a=0, so ker⁡(∂0)={(a,a)}. The same formula shows (a,a)=∂1(a), hence ker⁡(∂0)=im⁡(∂1).

2.1L2step 1.1algebra∎

Therefore H0(Hom⁡‾(C,C))=0. By [L2], applied in the abelian category Ab, this means Hom⁡K(Ab)(C,C)=0, so every endomorphism class of C is zero in the homotopy category.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources