Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Information gain on a singular prior support

Example

Assume AC. Let θ∼N2(0,C) with C=diag⁡(1,0), so its support is the first coordinate axis. Let η∼N(0,1) be independent of θ and compare the one-coordinate experiments Y=Aθ+η for A⊥=(0,1) and A∥=(1,0). Their expected information gains are 0 and 12log⁡2, respectively. The log-determinant formula remains defined although C is singular.

Facts & Assumptions

Given: AC, θ∼N2(0,C) with C=diag⁡(1,0), Y=Aθ+η with independent η∼N(0,1), and the two row operators in the Example.

[A1]

AC is inherited from the finite Gaussian and EIG/KL interfaces. The Axiom of Choice

[F1]

The support of Nn(m,C) is m+Ran⁡(C), including singular C. Support and pseudoinverse coordinates of a finite singular Gaussian

[F2]

For independent θ∼Nn(m0,C) and η∼Nm(0,Γ) with C⪰0 and Γ≻0, the linear-Gaussian EIG formula applies to Y=Aθ+η, including singular C. Linear Gaussian information gain has a log-determinant formula

[F3]

The natural logarithm is strictly increasing and log⁡1=0. Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm

Verification

Given: The hypotheses in the Example.

1.1A1F1givenalgebra

The range of C is span⁡{(1,0)T}, so [F1] gives the stated support. Also A⊥CA⊥T=0 and A∥CA∥T=1.

2.1A1F2step 1.1algebra

Applying [F2] with noise covariance 1 gives EIG⁡(A⊥)=12log⁡(1+0)=0 and EIG⁡(A∥)=12log⁡(1+1)=12log⁡2.

3.1F3step 2.1algebra∎

Since 2>1, [F3] gives log⁡2>log⁡1=0. The second coordinate therefore contributes no information under the prior, while the first-coordinate measurement has strictly positive EIG. No inverse or determinant of C is taken.

Depends on

Used by

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Dependency tree · two levels

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Sources