Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A diagonal inverse has an explicit Fourier truncation error

Example

Write ℓ2=ℓ2(N>0;R), where N>0={1,2,…}, so all sequence coordinates below have positive indices. Let p,s,R>0, let m≥1 be an integer, let θ∈ℓ2 satisfy ∑j≥1j2sθj2≤R2, and let (Apθ)j=j−pθj. Given data y=Apθ+η with ∥η∥ℓ2≤δ, the mesh-m truncated inverse is gm(y)=(jpyj)j≤m with zero output coordinates for j>m. It satisfies the continuum error bound ∥gm(y)−θ∥ℓ2≤mpδ+R(m+1)−s. This separates measurement-noise amplification from the mesh truncation tail; it makes no statistical or neural-operator claim.

Facts & Assumptions

Given: p,s,R>0, an integer m≥1, ∑j≥1j2sθj2≤R2, data y=Apθ+η, and ∥η∥ℓ2≤δ.

[A1]

gm(y) retains the first m coordinates jpyj and sets all later coordinates to zero.

Verification

1.1givenA1algebra

For j≤m, jpyj=θj+jpηj. The norm of the first-m noise vector is at most mp∥η∥ℓ2≤mpδ.

1.2givenA1algebra

The omitted truth tail satisfies ∑j>mθj2≤(m+1)−2s∑j>mj2sθj2≤R2(m+1)−2s. Its norm is at most R(m+1)−s.

2.1A1step 1.1step 1.2algebra∎

The error vector is the sum of the retained-coordinate noise error and the omitted truth tail. The triangle inequality with steps 1.1 and 1.2 gives ∥gm(y)−θ∥ℓ2≤mpδ+R(m+1)−s.

Used by

Nothing in the library uses this result yet.

Dependency tree · 0 levels

Nothing. This result depends on no other item in the library.