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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Power index functions give polynomial Bregman rates

Example

Let X,Y be real Banach spaces, D(F)⊆X, F:D(F)→Y, and let R:X→(−∞,+∞] be proper and convex. Fix x†∈D(F)∩dom⁡R, y=F(x†), ξ†∈∂R(x†), 1≤p<∞, A>0, 0<μ<1, 0≤β<1, and R0>R(x†). Write DRξ†(x,x†):=R(x)−R(x†)−⟨ξ†,x−x†⟩X∗,X, and suppose

−⟨ξ†,x−x†⟩X∗,X≤βDRξ†(x,x†)+A∥F(x)−F(x†)∥Ypμ(x∈D(F), R(x)≤R0).

For data yδ with ∥yδ−y∥Y≤δ, suppose 0≤εδ≤Cεδp and xαδ,ε∈D(F) satisfies Jαδ(xαδ,ε)≤inf⁡z∈D(F)Jαδ(z)+εδ, where Jαδ(x):=p−1∥F(x)−yδ∥Yp+αR(x). Set cp=21−p/p, H(q):=sup⁡s≥0(Asμ−qs), and choose α(δ)≍δp(1−μ). Then H(cp/α)≍δpμ and αH(cp/α)≍δp. The fixed-scale conjugate and penalty-index conditions hold. Hence DRξ†(xαδ,ε,x†)=O(δpμ) and ∥F(xαδ,ε)−yδ∥Y=O(δ); if DRξ†(x,x†)≥cR∥x−x†∥Xs on LR0 for constants cR,s>0, then ∥xαδ,ε−x†∥X=O(δpμ/s).

Facts & Assumptions

Given: The conditions in the Example hold, with α(δ)≍δp(1−μ).

[F1]

Variational source conditions yield nonlinear regularization rates: under the VSC, approximate-minimizer tolerance, and conjugate parameter coupling, the Bregman distance is O(H(cp/α)) and the residual is O(δ).

[F2]

A conjugate bound for residual and Bregman errors: H(q)=sup⁡s≥0(ψ(s)−qs) is the conjugate term in the residual/Bregman bound.

[A1]

A>0, 0<μ<1, and p≥1 are fixed, independent of δ.

Verification

1.1A1algebra

For q>0, the function s↦Asμ−qs has derivative Aμsμ−1−q, which decreases from +∞ to −q and vanishes only at sq=(Aμ/q)1/(1−μ). The function is increasing before sq and decreasing after it, with value 0 at s=0 and limit −∞ as s→∞, so this point is its global maximizer. Substitution gives H(q)=(1−μ)A1/(1−μ)μμ/(1−μ)q−μ/(1−μ).

2.1A1F1F2step 1.1algebra∎

With q=cp/α this gives H(cp/α)=Cp,A,μαμ/(1−μ), so the chosen α yields H(cp/α)≍δpμ and αH(cp/α)≍δp. Also H(cp/(2α))=2μ/(1−μ)H(cp/α), while ψ(C0δp)=AC0μδpμ=O(H(cp/α)) for every fixed C0>0. Thus the parameter and penalty conditions in [F1] hold, and [F1] gives the stated Bregman and residual rates. Under the additional lower bound with cR,s>0, division by cR gives ∥xαδ,ε−x†∥Xs=O(δpμ); taking the positive s-th root gives the norm rate.

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