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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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A restricted two-operator class with a positive stability modulus

Example

Let the truth space be U=[1,2]∪[4,5] with its absolute-value metric, the operator labels be A={1,2}, and the data space be R with its absolute-value metric. For each a∈A, define Fa:U→R by Fa(x)=ax. Let the truth-target map be qU:U→Q:=U, qU(x)=x. Restrict the admissible truth/operator pairs to C={(x,1):1≤x≤2}∪{(x,2):4≤x≤5}⊆U×A, with the restriction to C of the metric d1((x,a),(x′,a′))=∣x−x′∣+∣a−a′∣ on R2. The first-coordinate projection πU:C→U is bijective, since every x∈U occurs in exactly one admissible pair. Thus the configuration target qC:=qU∘πU:C→Q, given by qC(x,a)=x, is also bijective and has equality as its recovery equivalence. For the stability-modulus definition, take C as the parameter class, with configuration forward map G:C→R given by G(x,a)=Fa(x)=ax and target qC. Then ω(t)=t is a uniform stability modulus: for every c,c′∈C, ∣qC(c)−qC(c′)∣≤ω(∣G(c)−G(c′)∣).

Facts & Assumptions

Given: The truth space and target map qU, operator labels and maps Fa, restricted admissible-pair set C, configuration target qC, and configuration forward map G in the Example.

[F1]

Operator, noise-law, and prior-support mismatch: admissible truth/operator pairs may form a specified subset of the truth-space/operator-label product; each operator label gives a forward map on the truth space.

[F2]

Identifiability and stability moduli: for a parameter class with a target map and a forward map defined on that class, a uniform stability modulus is nondecreasing, vanishes at 0, tends to 0 as its argument decreases to 0, and bounds target distance by data distance for every pair in the class.

Verification

1.1givenF1F3algebra

By [F1], C is the specified admissible set of operator-labelled configurations. By [F3], d1 is a metric on R2; restricting its three metric axioms to C makes the restriction a metric. Each x∈U belongs to exactly one of [1,2] and [4,5], so it occurs in exactly one admissible pair. Thus πU and qC=qU∘πU are bijections onto U=Q, and equality is the stated recovery equivalence.

1.2givenF1F3algebra

If c=(x,1) and c′=(x′,1), then ∣qC(c)−qC(c′)∣=∣G(c)−G(c′)∣. If c=(x,2) and c′=(x′,2), then ∣qC(c)−qC(c′)∣=12∣G(c)−G(c′)∣≤∣G(c)−G(c′)∣.

1.3givenF3algebra

For c=(x,1) with 1≤x≤2 and c′=(x′,2) with 4≤x′≤5, we have ∣x′−x∣≤4 and ∣2x′−x∣≥2⋅4−2=6, so ∣qC(c)−qC(c′)∣≤∣G(c)−G(c′)∣. The reversed ordering follows by symmetry of absolute value.

2.1givenF2step 1.2step 1.3algebra∎

Steps 1.2 and 1.3 cover every pair in C, so ∣qC(c)−qC(c′)∣≤∣G(c)−G(c′)∣ for all c,c′. The function ω(t)=t is nondecreasing, satisfies ω(0)=0, and has lim⁡t↓0ω(t)=0; by [F2] it is the stated uniform stability modulus.

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