Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A proper Gaussian prior gives nonuniform finite-sample coverage on an unbounded truth class

Example

Fix n≥1, σ,τ>0, and 0<γ<1. Observe independent Yi∼N(θ,σ2) under truth θ∈R and use prior N(0,τ2). Let vn=(τ−2+nσ−2)−1, an=vnnσ−2, and zγ=Φ−1(1−γ/2), where Φ is the standard normal cumulative distribution function. The exact posterior credible interval is [anYˉ−zγvn,anYˉ+zγvn]. Since 0<an<1, its repeated-sampling coverage at fixed n tends to zero as ∣θ∣→∞, despite exact posterior computation and exact sampling.

Facts & Assumptions

Given: The scalar normal observation model and proper prior in the Example, with n≥1, σ,τ>0, and 0<γ<1.

[A1]

Completing the Gaussian likelihood and prior gives posterior mean anYˉ, variance vn=(τ−2+nσ−2)−1, and central credible radius rn=zγvn.

[A2]

The standard normal cumulative distribution has vanishing tails: Φ(t)→0 as t→−∞ and Φ(t)→1 as t→+∞.

Verification

1.1givenA1algebra

At every fixed n, an=nτ2/(σ2+nτ2) lies strictly between zero and one, and rn is finite and independent of the observation. Under truth θ, anYˉ−θ has mean −(1−an)θ and fixed positive standard deviation anσ/n.

1.2A1algebra

Standardizing the event in the Example gives cn(θ)=Φ ⁣(rn+(1−an)θanσ/n)−Φ ⁣(−rn+(1−an)θanσ/n).

2.1A1A2step 1.2algebra∎

As θ→+∞, both arguments in step 1.2 tend to +∞, so both cumulative probabilities tend to one by [A2] and their difference tends to zero. As θ→−∞, both arguments tend to −∞ and their difference again tends to zero. Thus the infimum coverage over θ∈R is zero at each fixed n.

Used by

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Dependency tree · 0 levels

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