Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Two direct white-noise functionals

Example

Take the single-parameter experiment with H=R2, its standard inner product, parameter set {x}, mean signal Kx=(m1,m2), and noise level ϵ>0. Let e1=(1,0), e2=(0,1), and g=ae1+be2 for a,b∈R. The direct observations Yx(e1) and Yx(e2) are independent with laws N(m1,ϵ2) and N(m2,ϵ2). In L2(P), Yx(g)=aYx(e1)+bYx(e2), with mean am1+bm2 and variance ϵ2(a2+b2); when a=b=0, Yx(g) is the constant zero.

Facts & Assumptions

[F1]

Isonormal Gaussian white-noise inverse experiment: The process is linear into L2(P), centered, has covariance E[Z(g)Z(h)]=⟨g,h⟩H, and has independent standard-normal coordinates on finite orthonormal tuples.

Given: The two-dimensional experiment, e1,e2, m1,m2, a,b, and ϵ>0 in the Example.

Verification

1.1givenF1

Since e1,e2 are orthonormal, [F1] gives independent standard-normal noises Z(e1),Z(e2). Each observation is an invertible affine function of its noise coordinate because ϵ>0, so it has the same generated sigma-algebra; the affine-image definition of N gives the two asserted laws and preserves independence.

2.1givenF1algebra∎

Linearity of the process gives Yx(g)=aYx(e1)+bYx(e2) as an equality of its almost-sure equivalence classes. The mean is am1+bm2, and the covariance identity in [F1] gives variance ϵ2∥ae1+be2∥2=ϵ2(a2+b2). If a=b=0, then g=0 and linearity gives Yx(0)=0.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources