Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A Latin-square assignment is a strict subset of RCBD assignments

Example

With treatments A,B,C, the cyclic array ABCBCACAB is a Latin square. The array with all three rows equal to A,B,C is an allowed RCBD assignment of three blocks, but is not a Latin square. Under the uniform RCBD law that particular assignment has probability 1/216; under the uniform Latin-square law it has probability zero.

Verification

Given: Three treatments, three blocks, and the two displayed assignments in the Example.

[F1] An RCBD assignment consists of an independently randomized treatment permutation in each block (Randomized complete-block design).

[F2] A Latin-square assignment uses every treatment once in every row and every column, and the specified law is uniform on all such squares (Randomized Latin-square design).

1.1F2given

In the cyclic array, each row and each column contains A,B,C once, so it belongs to the Latin-square sample space.

1.2F1F2given

In the repeated-row array, each row contains A,B,C once, so it is an RCBD assignment; each column repeats a single treatment, so it is not a Latin square.

2.1F1F2step 1.2algebra∎

There are 3!=6 permutations per RCBD block and the blocks are independently uniform, so the particular repeated-row assignment has probability 6−3=1/216. It has probability zero under a law supported only on Latin squares.

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Sources