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ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Lebesgue measure as Haar measure on rn

Example

Assume AC and n1. Lebesgue measure restricted to the Borel sets of (Rn,+) is a left and right Haar measure. All its Haar measures are positive multiples of Lebesgue measure, and the normalization μ([0,1]n)=1 singles out Lebesgue measure.

Facts & Assumptions

Given: n1 and AC.

[F1]

The Haar requirements are invariance, nonzeroness, compact finiteness and Radon regularity. (Left Haar integral and left Haar measure)

[F2]

Haar measures are positive scalar multiples. (Uniqueness of left Haar measure up to scale)

[F3]

Lebesgue measure is Radon under countable choice. (Lebesgue measure is a Radon measure on R^n)

[F4]

AC supplies countable choice and the uniqueness construction. (The Axiom of Choice)

[F5]

Lebesgue measure is translation invariant on measurable sets. (Lebesgue outer measure, Lebesgue measurability and Lebesgue measure are unchanged by translation)

Verification

technique · direct
1.1

Euclidean addition and negation are continuous; closed bounded cubes give compact neighbourhoods and the Euclidean metric is Hausdorff. By [F3], AC makes the Borel restriction of Lebesgue measure Radon. For a box B=j=1n[aj,bj], its defining volume is λn(B)=j(bjaj); in particular λn([0,1]n)=1, so the measure is nonzero.

F1F3F4
2.1

[F5] gives λn(E+h)=λn(E) for every Borel E and every h. Addition is commutative, so this is both left and right invariance. Thus [F1] identifies it as Haar, and [F2] gives μ=cλn for any Haar measure. On the unit cube μ([0,1]n)=c, forcing c=1 under the specified normalization. As an explicit translation calculation, λn(h+[0,2]n)=λn([0,2]n)=2n.

F1F2F4F5step 1.1

Sources

Knapp, Advanced Real Analysis, VI §2, pp.225–230, Lemmas 6.9–6.13. Local argument and conventions as displayed above.

Depends on

Used by

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Sources