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Twists on the two-affine projective line

Example

Assume the Axiom of Choice, inherited from the gluing construction. Let k be a field and let Pk1=U0∪U∞ be the two-affine projective line, with charts U0=Spec⁡k[t] and U∞=Spec⁡k[u], whose coordinates satisfy u=t−1 on the overlap W=U0∩U∞=Spec⁡k[t,t−1], and with O(n), n∈Z, the sheaves glued from the structure sheaves of the two charts by the frame relation e∞=tne0 (Two-affine projective line and its twists).

Then:

  1. For every n∈Z the sheaf O(n) is invertible, with e0 and e∞ nowhere-vanishing local generators on U0 and U∞; the relation inverts to e0=t−ne∞, and O(0)=OPk1 (Invertible sheaves).
  2. The dual has the negated index, O(n)∨≅O(−n), where O(n)∨=HomOX(O(n),OX) (The internal Hom sheaf of two module sheaves) and the dual frames satisfy e∞∨=t−ne0∨ on W.
  3. The tensor product adds the indices, O(n)⊗OXO(m)≅O(n+m), compatibly with the frames: e0(n)⊗e0(m)↦e0(n+m) and e∞(n)⊗e∞(m)↦e∞(n+m).
  4. In particular O(n)⊗O(−n)≅OX and O(n)∨∨≅O(n), and the example contains the degenerate values n=0 (trivial twist), n=1 (transition t) and negative n (transition tn=u−n).

Facts & Assumptions

Given: A field k; the two-affine projective line Pk1=U0∪U∞ with U0=Spec⁡k[t], U∞=Spec⁡k[u], u=t−1 on W=U0∩U∞; the sheaves O(n) for n∈Z with frames e0,e∞ related by e∞=tne0 on W.

[F1]

The two-affine definition (Two-affine projective line and its twists): the two charts cover Pk1 and intersect in W=Spec⁡k[t,t−1] with tu=1; for every n∈Z the sheaf O(n) is glued from OU0 and OU∞ with frames e0=1 on U0 and e∞=1 on U∞ related on W by e∞=tne0, equivalently e0=t−ne∞; each O(n) is free of rank one on each chart with the displayed frame, hence invertible, and O(0)=OPk1.

[F2]

Invertible means locally free of rank one (Invertible sheaves, Locally free sheaves of finite rank); the dual is L∨=HomOX(L,OX) (The internal Hom sheaf of two module sheaves), the tensor product of two invertible sheaves is invertible, and restriction to an open subscheme preserves invertibility.

[F3]

For an invertible L the evaluation morphism L∨⊗L→OX is an isomorphism, and the dual is described by transition units: if τi:L∣Ui→OUi are trivialisations with τi∘τj−1 equal to multiplication by the unit uij, then the induced trivialisations τi∨ of L∨ have transition units uij−1 (Dual of a line bundle is its tensor inverse).

[F4]

A gluing datum on an open cover consists of sheaves on the members and overlap isomorphisms satisfying the cocycle condition (A gluing datum for sheaves on an open cover); the glued sheaf exists and is unique up to unique isomorphism, so two sheaves of modules on X whose restrictions to the members of a common cover carry trivialisations with the same overlap identifications are canonically isomorphic (Compatible local sheaves glue uniquely up to unique isomorphism).

[F5]

Tensor product of modules and sheaves (Tensor product of sheaves of modules, Universal property of the tensor product for balanced maps into abelian groups): for a commutative ring R the multiplication R×R→R induces an isomorphism R⊗RR→R with 1⊗1↦1; consequently if F∣U and G∣U are free of rank one with generators e and f, then (F⊗OXG)∣U is free of rank one with generator e⊗f, because restriction commutes with the tensor-product construction.

[F6]

The Axiom of Choice as used by the gluing construction of [F1] and the existence theorem of [F4] (The Axiom of Choice).

Proof technique: direct; read off the transition units of frames, multiply them for the tensor product and invert them for the dual, then apply the uniqueness of glued sheaves.

Proof

1.1F1F2

The transition units: on the overlap W=Spec⁡k[t,t−1] the element t is a unit with inverse u, so for every n∈Z the relation e∞=tne0 of [F1] is a relation between generators of free rank-one modules and inverts to e0=t−ne∞; the two charts cover Pk1, so each O(n) is locally free of rank one with the displayed frames, hence invertible, and O(0)=OPk1.

2.1F1F4F5step 1.1

The tensor product adds the indices: fix n,m∈Z and write e0(n) and e∞(n) for the frames of O(n), and similarly for m; by [F5] the tensor product O(n)⊗O(m) is free of rank one on U0 with generator g0=e0(n)⊗e0(m), and free of rank one on U∞ with generator g∞=e∞(n)⊗e∞(m). On W the frame relations give g∞=(tne0(n))⊗(tme0(m))=tn+mg0, and inverting gives g0=t−(n+m)g∞, so the trivialisations of O(n)⊗O(m) on the two charts have exactly the overlap identification e∞(n+m)=tn+me0(n+m) that defines O(n+m) in [F1]; by the uniqueness clause of [F4] there is a canonical isomorphism O(n)⊗O(m)≅O(n+m) carrying g0 to e0(n+m) and g∞ to e∞(n+m).

2.2F1F2F3F4step 1.1

The dual negates the index: since O(n) is invertible with the trivialisations determined by the frames e0 and e∞, its dual O(n)∨ is invertible and free of rank one on each chart with the dual frames e0∨ and e∞∨ characterised by e0∨(e0)=1 and e∞∨(e∞)=1 [F2, F3]. On W one has e∞=tne0, hence (t−ne0∨)(e∞)=t−ne0∨(tne0)=t−ntn=1, and since the dual is free of rank one there the section with this property is unique, so e∞∨=t−ne0∨; equivalently e0∨=tne∞∨, which is the overlap identification defining O(−n) in [F1], so the uniqueness clause of [F4] gives a canonical isomorphism O(n)∨≅O(−n) carrying e0∨ to the frame of O(−n) on U0 and e∞∨ to its frame on U∞.

3.1F1F2F3F6step 1.1step 2.1step 2.2∎

The degenerate values and choice accounting: taking n=0 in step 2.1 gives O(0)⊗O(m)≅O(m), and O(0)=OPk1 by step 1.1, so O(0) is the tensor unit; taking m=−n and using step 2.2 gives O(n)⊗O(−n)≅O(n)⊗O(n)∨≅O(0)=OX, in agreement with the evaluation isomorphism O(n)∨⊗O(n)→OX of [F3], whose transition unit is tnt−n=1; applying step 2.2 twice gives O(n)∨∨≅O(−n)∨≅O(n); for n=1 the transition is t and for negative n it is tn=u−n with u=t−1, both units on W. All frames, transition units and isomorphisms used above come from the fixed two-chart cover and the canonical dual and tensor structures, so no selection is made and the only use of the Axiom of Choice is the inherited one recorded in [F6].

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