Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A line segment has length equal to the distance between its endpoints, and a finitely piecewise-linear path has length equal to the sum of its edge lengths

Example

For p,q∈Rn, the line segment γ(t)=(1−t)p+tq on [0,1] has

L(γ)=∥q−p∥2.

More generally, a polygonal path with successive vertices p0,…,pm, traversing each segment once and in that order on adjacent parameter subintervals, has

L=∑i<m∥pi+1−pi∥2.

For m=0 the path is constant and the empty sum is zero.

Facts & Assumptions

Given: The segment or polygonal path in the statement.

[L1]

A piecewise C1 path has length equal to the sum of the integrals of the speeds on its pieces (A continuous piecewise-C1 path is rectifiable and its length is the sum of the speed integrals over its pieces).

[L2]

Length is additive over adjacent parameter subintervals (Arc length is additive across every subdivision point and decreases under restriction).

Verification

technique · direct
1.1

The segment derivative is the constant vector q−p, so [L1] gives L(γ)=∫01∥q−p∥2 dt=∥q−p∥2.

givenL1algebra
2.1

On a polygonal path, the i-th affine piece has length ∥pi+1−pi∥2 by step 1.1, independently of its positive traversal time.

step 1.1algebra
3.1

Add the piece lengths using [L1] or [L2] to obtain the displayed sum. If m=0, the path is constant and both sides are zero.

step 2.1L1L2∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources