Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A mixed-sign vorticity is not a probability for W1

Example

On R2, let ω=δ0−δ(1,0). It is a nonzero finite signed measure of total mass zero and total variation two. The probability W1 in The coupling definition of the 1-Wasserstein distance cannot be applied to ω.

Facts & Assumptions

Given: The signed measure ω of the Example.

[F1]

W1 is defined only for probability measures with finite first moment (The coupling definition of the 1-Wasserstein distance).

[F2]

dBL is the dual supremum over functions bounded by one with Lipschitz constant at most one (Bounded-Lipschitz dual discrepancy for finite signed measures).

[F3]

Total variation is the supremum over measurable partition sums (The total variation |nu|(E) from countable measurable partitions).

[F4]

The reverse triangle inequality gives ∣∣x∣−∣y∣∣≤∣x−y∣ for the Euclidean norm (Cauchy-Schwarz ∣⟨x,y⟩∣≤∥x∥2∥y∥2 with its equality case, the triangle inequality for ∥⋅∥2, the parallelogram law and polarisation).

Verification

Given: ω=δ0−δ(1,0).

1.1givenF1F3algebra

Among any countable partition, at most two cells have nonzero signed mass, each of magnitude one; the partition into the two singleton atoms and their complement attains the sum two. Thus ∣ω∣(R2)=2 by [F3], while its signed mass is 1−1=0. Therefore ω is neither a nonnegative probability measure nor normalizable by its net mass, so the domain condition in [F1] fails.

2.1F2F4step 1.1algebra∎

The function ϕ(x)=min⁡(1,∣x∣) is bounded by one and 1-Lipschitz by [F4], with ϕ(0)=0 and ϕ(1,0)=1. Hence ∣∫ϕdω∣=1, so dBL(ω,0)≥1. This finite signed dual quantity remains meaningful by [F2], whereas probability W1(ω,0) is undefined.

Depends on

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Dependency tree · two levels

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