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p4 and p4m orientation-indexed feature maps

Example

Let ρ=(0−110) be the quarter-turn, σ=(100−1) a reflection, e1=(1,0), and e2=(0,1); define δa(x)=1 when x=a and 0 otherwise. The ordinary planar cross-correlation (f⋆ψ)(x)=∑y∈Z2f(y)ψ(y−x) with f=δ0 and ψ=δe1 is not rotation-equivariant with a fixed filter: Lρf=f, but f⋆ψ=δ−e1 and Lρ(f⋆ψ)=δ−e2≠δ−e1=(Lρf)⋆ψ. In a p4 group layer, the feature map is indexed by pairs (t,ρj), giving four orientation indices at each translation t∈Z2; in a p4m group layer it is indexed by (t,ρjσϵ) for ϵ∈{0,1}, giving eight. The full p4 and p4m groups remain infinite through their translations, and their group-correlation layers are equivariant for the full left action.

Facts & Assumptions

Given: The p4/p4m groups, feature-map actions, planar correlation, and group-correlation theorem described in the Example. Verify the orientation counts, group-layer equivariance, and fixed-filter rotation failure.

[F1]

The p4 and p4m square-lattice symmetry groups: The point groups are C4={ρj} and D4={ρj,ρjσ}; the full groups contain every translation and are infinite.

[F2]

The left action on feature maps induced by an action on sites: The action on a feature map is (Luf)(x)=f(u−1⋅x).

[F3]

Discrete convolutional layer with local receptive fields, channel mixing, stride, and padding: On the full lattice with unit stride, a finite receptive-field layer computes a discrete cross-correlation without kernel reversal.

[F4]

First-layer and group-to-group cross-correlation: Group-to-group cross-correlation uses (CΨf)(g)=∑h∈Gf(h)Ψ(g−1h).

[F5]

Group cross-correlation and compatible layers are equivariant: Group-to-group cross-correlation commutes with the left action whenever its sum is finite or absolutely convergent.

Verification

1.1givenF1algebra

At a fixed translation t, the p4 index has the four values ρj and p4m has the eight distinct values ρjσϵ, by [F1]. Distinct translations give infinitely many full group elements in each case.

1.2givenF2F4F5

For either full group G=PC4 or PD4, apply [F5] to the group-correlation operator in [F4]. Its input and output actions are the left actions in [F2], so every such group layer is equivariant without treating G as finite.

2.1givenF2F3algebra∎

Since ρ(0)=0, Lρδ0=δ0. In the displayed planar correlation, only y=0 contributes, and δe1(e1)=1, so δ0⋆δe1=δ−e1. Therefore Lρ(δ0⋆δe1)=δρ(−e1)=δ−e2, whereas (Lρδ0)⋆δe1=δ−e1. As e1≠e2, these outputs differ.

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