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ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-30
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A nilpotent irrelevant ideal gives empty Proj

Example

Let k be a field and let S=k[ε]/(ε2) be graded by deg⁡ε=1 and deg⁡k=0, so that S0=k and S+=(ε) with ε2=0. Then S+ is a nilpotent ideal, Proj⁡S=∅, and yet Spec⁡S is nonempty: the ring k[ε]/(ε2) has the single prime ideal (ε). So emptiness of Proj is not emptiness of the spectrum, and it is detected by the nilpotency of the irrelevant ideal.

Facts & Assumptions

Given: A field k, the graded ring S=k[ε]/(ε2) with deg⁡ε=1.

[F1]

Proj⁡S is the set of homogeneous prime ideals p with S+⊈p; a prime contains every nilpotent element; and S=⨁d≥0Sd with S1=kε and Sd=0 for d≥2. (Points of Proj of a graded ring)

[F2]

Proj⁡S=∅ if and only if every homogeneous element of S+ is nilpotent; if S+ is finitely generated this is equivalent to S+ being nilpotent. (Empty Proj and irrelevant torsion)

[F3]

In the ring k[ε]/(ε2) every prime ideal contains ε, so (ε) is the unique prime, and it is maximal; the localisation Sε is the zero ring. [algebra]

Verification

technique · direct: identify $S_+$, apply the emptiness criterion, and exhibit the point of $\operatorname{Spec}S$
1.1algebra

The irrelevant ideal is nilpotent. Here S+=kε consists of the multiples of ε, and S+2=kε2=0; hence every element of S+ is nilpotent and S+=(ε) is finitely generated.

1.2F1F3algebra

The standard chart is empty. For the homogeneous element ε of degree 1 we have S(ε)=(S[ε−1])0, and S[ε−1]=0 because ε is nilpotent; hence D+(ε)=Spec⁡S(ε)=Spec⁡0=∅, and since ε generates S+ this is the only standard open.

2.1F1F2step 1.1

Proj is empty. By step 1.1 every homogeneous element of S+ is nilpotent, so [F2] gives Proj⁡S=∅; equivalently, any homogeneous prime p⊆S contains the nilpotent ε, hence contains S+=(ε) and is excluded from Proj⁡S.

3.1F1F3algebra

The spectrum is nonempty. In k[ε]/(ε2) the element ε is nilpotent but nonzero, so the ideal (ε) is proper; every prime contains the nilpotent ε, so (ε) is the unique prime ideal and Spec⁡S={(ε)}≠∅, in contrast with step 2.1.

4.1

Conclusion. Steps 1.1 and 2.1 show that the nilpotent irrelevant ideal produces empty Proj, while step 3.1 shows that the underlying ring still has a point; the two conclusions are consistent because Proj discards exactly the primes containing all of S+. [F1, F2, step 2.1, step 3.1] \qed

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources