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ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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For a finite p-group, the augmentation map from kP to the trivial module is its projective cover

Example

Let P be a finite p-group and let k have characteristic p. Then the augmentation map

ε:kPk

is the projective cover of the trivial module.

Facts & Assumptions

Given: A finite p-group P, a field k of characteristic p, and the augmentation map ε:kPk.

[L3]

Projective covers exist and are unique up to isomorphism over the target (Every finite-dimensional module has a projective cover, unique up to isomorphism over the target).

Verification

technique · direct
1.1

The regular module kP is projective, and ε is surjective onto the trivial module. Its kernel is the augmentation ideal, which is the unique maximal ideal because [L2] makes kP local. Hence the kernel is superfluous.

L2givenalgebra
2.1

By step 1.1, ε is a projective cover of the trivial module. The uniqueness theorem [L3] says every projective cover of that target is isomorphic to this one over the target.

L3step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources