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ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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For a finite p-group, the augmentation map from kP to the trivial module is its projective cover

Example

Let P be a finite p-group and let k have characteristic p. Then the augmentation map

ε:kP→k

is the projective cover of the trivial module.

Facts & Assumptions

Given: A finite p-group P, a field k of characteristic p, and the augmentation map ε:kP→k.

[L3]

Projective covers exist and are unique up to isomorphism over the target (Every finite-dimensional module has a projective cover, unique up to isomorphism over the target).

Verification

technique · direct
1.1L2givenalgebra

The regular module kP is projective, and ε is surjective onto the trivial module. Its kernel is the augmentation ideal, which is the unique maximal ideal because [L2] makes kP local. Hence the kernel is superfluous.

2.1L3step 1.1∎

By step 1.1, ε is a projective cover of the trivial module. The uniqueness theorem [L3] says every projective cover of that target is isomorphic to this one over the target.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources