Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passverified 2026-09-26 (gpt-6-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Projective linear actions and Iwasawa's hypotheses

Example

Let q>3, let G=PSL⁡2(Fq), and let P1(Fq)=Fq∪{∞}. The usual fractional linear action of G on P1(Fq) is doubly transitive and therefore primitive. The stabilizer of ∞ contains the translation subgroup A:={ x↦x+b:b∈Fq }, which is abelian and normal there, and the conjugates of A generate G. So this action satisfies the hypotheses of Iwasawa's criterion.

Facts & Assumptions

Given: The action of PSL⁡2(Fq) on P1(Fq) by fractional linear transformations.

[L1]

Every doubly transitive action is primitive (Every doubly transitive action is primitive).

[L2]

Iwasawa's criterion applies to a faithful primitive action when the point stabilizer contains a nontrivial abelian normal subgroup whose conjugates generate the whole group (Iwasawa's simplicity criterion for primitive actions).

Verification

technique · direct
1.1L1givenalgebra

The matrices (1b01) give translations x↦x+b, so the stabilizer of ∞ is transitive on Fq. The matrix (0−110) sends ∞ to 0; composing it with translations sends ∞ to any finite point. All these matrices have determinant one, so they act through G, not merely through the full projective linear group. Hence the action is transitive, and its point stabilizer is transitive on the other points: it is doubly transitive and therefore primitive by [L1]. A fractional linear map fixing ∞, 0, and 1 is scalar as a matrix, hence the projective action is faithful.

1.2givenalgebra

The subgroup A fixes ∞, is abelian under composition, and is normal in the stabilizer of ∞ because conjugating a translation by an affine map gives another translation.

2.1L2step 1.1step 1.2∎

Conjugating A by the inversion x↦−1/x gives the lower-unitriangular subgroup. The upper and lower unitriangular subgroups generate SL⁡2(Fq) by Gaussian elimination, so their projective images generate G. Thus the conjugates of A generate G, and [L2] applies.

Depends on

Used by

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Dependency tree · two levels

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Sources