Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Cancelling identity padding fixes the LCU scale

Example

For the truncated Taylor LCU in Finite Taylor LCU polynomial, suppose its listed coefficient norm is sK=∑k=0K(Λ∣h∣)kk!≤2. Set q=(2−sK)/2 and append two distinct identity entries with coefficients +q and −q. The represented polynomial is unchanged while its listed coefficient norm becomes exactly 2.

For example, take the one-term Hamiltonian H=1⋅Z, h=log⁡2, and K=0. Then M0=I, s0=1, and the padded list (1I,12I,−12I) still sums to I and has absolute coefficient sum 2.

Facts & Assumptions

Given: A truncated Taylor LCU whose listed coefficient norm satisfies sK≤2.

[F1]

Finite Taylor LCU polynomial: the k=0 term is the empty tuple with coefficient 1 and unitary I, and the listed coefficient norm is sK(h)=∑k=0K(Λ∣h∣)k/k!.

[F2]

The Pauli matrices: in the ordered qubit basis, Z=(100−1).

[F3]

The natural logarithm as the inverse of the exponential function: for x>0, log⁡x is the real number whose exponential is x.

Verification

Given: As in Facts & Assumptions.

1.1givenF1algebra

The hypothesis sK≤2 gives q=(2−sK)/2≥0.

2.1givenF1step 1.1algebra

The two appended terms add qI−qI=0 to the matrix and add ∣q∣+∣−q∣=2q=2−sK to the coefficient norm. The new norm is therefore sK+(2−sK)=2, including q=0.

3.1givenF1F2F3step 2.1algebra∎

In the stated example, [F2] gives Z†=Z and Z†Z=I, so H=1⋅Z is a valid one-term Hamiltonian with Λ=1; [F3] makes h=log⁡2 a real parameter. Since K=0, [F1] gives M0=I and s0=1. Hence q=1/2; the three coefficients sum to 1 and their absolute values sum to 1+1/2+1/2=2.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources