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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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A quadratic Fourier product aliases two high modes on an even grid

Example

On the N=4 periodic grid, let p(x)=cos⁡x+cos⁡(2x). The continuous square has modes through frequency four, but its grid interpolant is

I4(p2)=32+2cos⁡x+12cos⁡(2x).

The frequency-three mode aliases to frequency one, and the frequency-four mode aliases to the constant mode. This exact sample identity is not a de-aliasing or nonlinear stability result.

Facts & Assumptions

Given: The four-point grid xj=πj/2, the interpolant convention, and p(x)=cos⁡x+cos⁡(2x).

[F1]

Periodic Fourier collocation grid and even-grid Nyquist convention: for N=4, the interpolation space is spanned over R by 1,cos⁡x,sin⁡x,cos⁡(2x).

[F2]

Periodic Fourier modes alias modulo the grid size: modes whose integer frequencies are congruent modulo 4 have the same samples, and sampled products have frequency equal to the sum modulo 4.

[F3]

The addition formulas for sine and cosine: cos⁡ucos⁡v=12(cos⁡(u+v)+cos⁡(u−v)).

[F4]

Quarter-turn values and shifts by pi/2 and pi: on xj=πj/2, cos⁡(4xj)=1 and cos⁡(3xj)=cos⁡(xj).

Proof

1.1F3algebra

By [F3], p(x)2=cos⁡2x+2cos⁡xcos⁡(2x)+cos⁡2(2x)=1+cos⁡x+12cos⁡(2x)+cos⁡(3x)+12cos⁡(4x).

2.1givenF1F4step 1.1algebra

At every grid node [F4] turns this into p(xj)2=32+2cos⁡(xj)+12cos⁡(2xj). The right side belongs to [F1]'s interpolation space.

3.1F1F2step 1.1step 2.1algebra∎

The modes at frequencies 3 and 4 in step 1.1 are identified on the grid by the congruences 3≡−1(mod4) and 4≡0(mod4), exactly as [F2] states. Thus the displayed interpolant has the same samples as p2, with the two alias contributions combined.

Depends on

Used by

Nothing in the library uses this result yet.

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Sources