Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The rank map on a disconnected compact space

Example

Let X be compact Hausdorff and let X=X1⨿X2, where X1 and X2 are nonempty clopen subspaces. The bundle that is ε1 on X1 and ε2 on X2 has rank class

(1X1,2X2)∈H0(X1;Z)×H0(X2;Z)≅H0(X;Z).

Thus the rank map on a disconnected compact space is genuinely a locally constant function and cannot in general be replaced by one integer.

Facts & Assumptions

Given: the stated compact Hausdorff space and clopen decomposition with both pieces nonempty.

[F1]

The rank homomorphism sends a bundle to its integer-valued fiber-dimension function, viewed in H0, and respects virtual differences (Grothendieck ring structure and rank map).

[F2]

Bundles of locally constant finite rank, including rank zero, are admitted componentwise in the Whitney-sum monoid (The Whitney-sum monoid of complex vector bundles).

Verification

technique · direct construction and calculation
1.1F2construct

Form E=(X1×C)⨿(X2×C2) with projection to X. Since X1 and X2 are disjoint open subsets, these product charts make E a complex vector bundle whose fiber dimension is 1 on X1 and 2 on X2.

2.1F1step 1.1

Degree-zero cohomology of a disjoint union is the product of the degree-zero groups, and the fiber-dimension function in step 1.1 corresponds to (1X1,2X2). Therefore [F1] gives the displayed rank class.

3.1step 2.1algebra∎

If this class came from one integer m, its restrictions to both nonempty pieces would be the same constant m. Step 2.1 would force simultaneously m=1 and m=2, a contradiction. Hence a single global integer cannot encode rank in general.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources