Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-22
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Root-space brackets for matrix units

Example

In sln(C) with the diagonal Cartan subalgebra h and roots εiεj of Diagonal Cartan subalgebra and roots of sl_n, the matrix units satisfy [Eij,Ekl]=δjkEilδliEkj, and the bracket of the root lines gεiεj=CEij and gεkεl=CEkl lies in the root space of the sum of the two functionals, as required by Brackets of root spaces: [gεiεj,gεkεl]g(εiεj)+(εkεl). For kj and li both sides vanish; for k=j and li the bracket is CEil, whose root is εiεl=(εiεj)+(εjεl).

Facts & Assumptions

Given: The algebra sln(C) with its diagonal Cartan subalgebra and roots εiεj as in Diagonal Cartan subalgebra and roots of sl_n, the root lines gεiεj=CEij, and the inclusion [gα,gβ]gα+β of Brackets of root spaces; the root-space convention is Root and root space.

Verification

technique · direct
1.1

The product formula EijEkl=δjkEil is immediate from matrix multiplication: the product has the single nonzero entry 1 in position (i,l) exactly when the middle indices match. Hence [Eij,Ekl]=δjkEilδliEkj.

givenalgebra
2.1

There are four cases. If k=j and li, then [Eij,Ejl]=Eil and the root is (εiεj)+(εjεl)=εiεl. If l=i and kj, then [Eij,Eki]=Ekj and the root is (εiεj)+(εkεi)=εkεj. If k=j and l=i, then [Eij,Eji]=EiiEjjh=g0 and the functional sum is zero. Finally, if kj and li, both Kronecker terms vanish; the functional sum has no cancellation producing a root or zero, so its root space is zero. Thus every case has the asserted bracket inclusion.

givenstep 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources