Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Softened Newtonian particles do not specify the physical collision force

Example

For two Newtonian point masses in R3 with positive constants absorbed into c>0, the unsoftened relative acceleration is F(r)=−c r/∣r∣3 for r≠0, where ∣⋅∣ is Euclidean. A softened model uses Fε(r)=−cr(∣r∣2+ε2)3/2,ε>0. The softened field is smooth at a collision, but it defines a different dynamical model.

Facts & Assumptions

Given: c>0, ε>0, and the two displayed force laws.

Verification

Given: The unsoftened and softened force formulas in the Example.

1.1givenF1algebra

For r≠0, their scalar denominators are ∣r∣3 and (∣r∣2+ε2)3/2, which differ because ε>0. Thus Fε(r)≠F(r) for every nonzero r.

2.1givenstep 1.1algebra∎

At r=0, the unsoftened formula is undefined, whereas the softened formula gives Fε(0)=0. The denominator ∣r∣2+ε2 is smooth and strictly positive, and u↦u−3/2 is smooth for u>0; hence the softened field is C∞ on all of R3. Its smooth extension therefore supplies a convention for its own regularized model, not a collision law for the singular Newtonian system.

Depends on

Used by

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Dependency tree · two levels

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