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Störmer–Verlet has bounded oscillatory energy error on the harmonic oscillator

Example

For H(q,p)=12(q2+p2), use the real-parameter kick and drift shears of One-step leapfrog map as force and drift shears and define the signed kick-drift-kick step Sh:=Kh/2∘Dh∘Kh/2 for real h; for h>0 this is the published one-step map, and for h<0 it is its same-form signed-step extension. If 0<∣h∣<2, this step preserves the positive quadratic form H~h(q,p)=12((1−h2/4)q2+p2). Consequently its original-energy error is bounded uniformly over all step counts by ∣H(qn,pn)−H(q0,p0)∣≤h28(2H~h(q0,p0)1−h2/4+q02).

Facts & Assumptions

Given: The published kick-drift-kick map, M=1, V(q)=q2/2, and 0<∣h∣<2.

[F1]

The force kicks and drifts are defined for real parameters, with formulas Ka(q,p)=(q,p−aq) and Db(q,p)=(q+bp,p); their signed composition is Sh=Kh/2∘Dh∘Kh/2. For h>0 it is the one-step map in One-step leapfrog map as force and drift shears.

Verification

1.1F1givenalgebra

The first kick gives p1/2=p−hq/2, the drift gives q1=q+hp1/2=(1−h2/2)q+hp, and the last kick gives p1=p1/2−hq1/2=−h(1−h2/4)q+(1−h2/2)p. Thus Sh=(ah−hsa),a=1−h2/2,s=1−h2/4.

2.1step 1.1algebra

Direct multiplication gives ShT(s001)Sh=(s(a2+h2s)00a2+h2s)=(s001), because a2+h2s=1. Hence H~h is exactly invariant. Since s>0, invariance implies qn2≤2H~h(q0,p0)/s for every n.

3.1step 2.1algebra∎

The identity H~h=H−(h2/8)q2 gives H(qn,pn)−H(q0,p0)=h28(qn2−q02). Apply the bound from step 2.1 and the triangle inequality to obtain the stated uniform error estimate.

Depends on

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