Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A canonical map between two bracketings of a five-fold product

Example

Take the two parenthesisations u:=((A⊗(B⊗C))⊗(D⊗E)),v:=A⊗(B⊗(C⊗(D⊗E))). A canonical map u→v is obtained by associators alone.

Facts & Assumptions

Given: Objects A,B,C,D,E of a monoidal category.

[L1]

Between any two parenthesisations of one ordered tensor word there is a unique canonical natural isomorphism (Mac Lane coherence in canonical-map form).

Verification

technique · direct
1.1given

Apply the outer associator to obtain ((A⊗(B⊗C))⊗(D⊗E))→αA,B⊗C,D⊗EA⊗((B⊗C)⊗(D⊗E)).

2.1step 1.1

Apply 1A⊗αB,C,D⊗E to the result of step 1.1 and get A⊗((B⊗C)⊗(D⊗E))→A⊗(B⊗(C⊗(D⊗E)))=v.

3.1L1step 2.1∎

The composite of steps 1.1 and 2.1 is therefore a canonical map u→v. Any other chain of associators with the same endpoints is equal to it by [L1].

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources