Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passaudited 2026-08-28
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The holomorphic hull of a product torus in the bidisc is the closed polydisc it bounds

Example

Fix radii 0<r1,r2<1 in the bidisc D2, and let

T={(z1,z2)∈C2:∣z1∣=r1, ∣z2∣=r2}.

Then the holomorphic hull of T in D2 is

T^D2={(z1,z2)∈C2:∣z1∣≤r1, ∣z2∣≤r2}.

Facts & Assumptions

Given: The product torus T in the bidisc D2.

[L1]

Hull membership is tested against all holomorphic functions on the ambient domain (Holomorphic hulls and holomorphic convexity).

[L2]

On a closed polydisc, the supremum of a holomorphic function is attained on the distinguished boundary (The modulus of a holomorphic function on a closed polydisc is bounded by its supremum on the distinguished boundary).

Verification

technique · direct
1.1L1L2given

Let P={(z1,z2):∣z1∣≤r1, ∣z2∣≤r2}. If a∈P and f is holomorphic on D2, then f is continuous on the closed polydisc P, and the distinguished boundary of P is exactly T. Therefore [L2] gives ∣f(a)∣≤sup⁡T∣f∣. By [L1], every point of P lies in T^D2.

2.1L1step 1.1algebra∎

If a=(a1,a2) lies in D2∖P, then either ∣a1∣>r1 or ∣a2∣>r2. In the first case the holomorphic coordinate function f(z1,z2)=z1 satisfies ∣f(a)∣>sup⁡T∣f∣, and in the second case f(z1,z2)=z2 does the same. Hence [L1] excludes every point outside P from the hull. Together with step 1.1, this identifies T^D2 exactly.

Depends on

Used by

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Dependency tree · two levels

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Sources