Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A lower bound of size 2clog⁡2n log⁡2log⁡2n is still subpolynomial in n

Example

Fix c,ε>0. Then the function 2clog⁡2n log⁡2log⁡2n still grows more slowly than nε.

Facts & Assumptions

Given: Positive reals c and ε.

[L1]

For n>2, both log⁡2n and log⁡2log⁡2n are defined (The logarithm to a positive base other than one).

Verification

technique · direct
1.1L1algebra

Write n=2L with L:=log⁡2n. Then 2cLlog⁡2L/nε=2cLlog⁡2L−εL.

2.1step 1.1algebra

For L≥16, one has log⁡2L≤L, so Llog⁡2L≤L3/4. If moreover L≥(2c/ε)4, then cL3/4≤(ε/2)L, and therefore cLlog⁡2L−εL≤−(ε/2)L. Hence for all sufficiently large n, 2clog⁡2n log⁡2log⁡2n/nε≤1/nε/2, which tends to 0.

3.1step 2.1∎

Therefore 2clog⁡2n log⁡2log⁡2n=o(nε).

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources