Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-08-29
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The n-sphere with its standard smooth atlas

Example

For n≥1, let

Sn:={(x1,…,xn+1)∈Rn+1:x12+⋯+xn+12=1}.

With north and south poles N=(0,…,0,1) and S=(0,…,0,−1), the stereographic charts

σN(x)=(x1,…,xn)1−xn+1,σS(x)=(x1,…,xn)1+xn+1

define a smooth atlas on Sn. Their overlap transition is u↦u/∥u∥2 on Rn∖{0}.

Facts & Assumptions

Given: The sphere Sn and the two stereographic maps σN,σS.

[F1]

A smooth atlas is a covering family of pairwise smoothly compatible charts (Smooth atlases).

[F2]

Smooth compatibility means that both transition maps are smooth on the overlap (Smoothly compatible charts and the smoothness of Euclidean transition maps).

[F3]

A smooth manifold is a topological manifold equipped with a smooth structure (Smooth manifolds and their smooth charts).

Verification

technique · direct
1.1given

The domains Sn∖{N} and Sn∖{S} are open and cover [given] Sn. The inverse formulas σN−1(u)=(2u1+∥u∥2,∥u∥2−11+∥u∥2),σS−1(u)=(2u1+∥u∥2,1−∥u∥21+∥u∥2) show that both maps are homeomorphisms onto Rn.

2.1F1F2step 1.1

On the overlap the transition maps are σS∘σN−1(u)=u∥u∥2,σN∘σS−1(u)=u∥u∥2, defined on Rn∖{0}, so they are smooth rational maps there. Hence the two stereographic charts are smoothly compatible by [F2], and [F1] makes them a smooth atlas on Sn.

3.1F3step 2.1∎

Therefore Sn is a smooth manifold by [F3].

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources