Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The quotient-witness reduction in a three-block configuration

Example

Take original blocks A1,A2,B and outside vertices x,y,u with the following adjacency pattern:

  1. each of A1, A2, and B induces a connected subgraph;
  2. A1 and A2 are mixed;
  3. B is complete to A1 and anticomplete to A2;
  4. x and y are nonadjacent and both are complete to A1A2B;
  5. u is adjacent to x, nonadjacent to y, complete to A1A2, and anticomplete to B.

Then the quotient blocks are D1:=A1A2 and D2:=B, and the quotient-level witness descends to the original mixed pair A1,A2.

Facts & Assumptions

Given: The three-block configuration described in the Statement.

[L1]

Mixed original blocks lie in one quotient block, so A1 and A2 merge into D1, while B stays separate because it is pure to each of A1 and A2 (The quotient blockade obtained from mixed-block reachability).

[L2]

The descent lemma turns a quotient-level witness on D1,D2 into a witness on mixed original blocks inside D1 (A quotient-level mixed-block witness descends to two mixed member blocks).

Verification

technique · direct
1.1

By item 2 of the configuration and [L1], the two original blocks A1,A2 form one quotient block D1=A1A2, while D2=B is the other quotient block. Because B is complete to A1 and anticomplete to A2, the quotient blocks D1 and D2 are mixed.

givenL1
2.1

Item 1 of the configuration says that every original block of the blockade is connected, so the connectivity hypothesis of [L2] holds. No vertex of D1 is mixed on D2: every vertex of A1 is complete to B, and every vertex of A2 is anticomplete to B. The outside vertices satisfy the remaining hypotheses of [L2]: x and y are nonadjacent and complete to D1D2, while uN(x)N(y) is complete to D1 and anticomplete to D2.

step 1.1given
3.1

Applying [L2] therefore yields mixed original blocks A1,A2 inside D1 and vertices x,y,u outside A1A2 with the required adjacency pattern. Thus the quotient-level witness has been pushed down to a witness on the original mixed pair inside D1.

step 2.1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.