Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedverified 2026-09-26 (gpt-6-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The split extension as the zero cocycle

Example

When f=0, the twisted product M×fG is the semidirect product M⋊G, so it represents the zero class in H2(G,M).

Facts & Assumptions

Given: A group G, an abelian G-module M, and the zero function f(g,h)=0.

[F1]

The twisted product uses the multiplication (m,g)(n,h)=(m+g⋅n+f(g,h),gh) (Twisted product extension from a two-cocycle).

[F2]

H2(G,M) is the quotient of normalized two-cocycles by two-coboundaries, so the zero cocycle represents its zero class (Second cohomology by factor sets).

[L1]

An extension with a specified normalized section has the cohomology class of that section's factor set, independently of the chosen normalized section (An extension determines a well-defined H^2 class).

Verification

technique · direct
1.1F1given

With f=0, [F1] becomes (m,g)(n,h)=(m+g⋅n,gh), which is the usual semidirect-product law on M⋊G.

2.1F1F2L1step 1.1algebra

The explicit normalized section s(g)=(0,g) is a homomorphism, so the extension splits. Its factor set is identically zero because s(g)s(h)=s(gh); [L1] assigns the extension the class [0], which is the zero class by [F2]. This uses the displayed section and needs no choice of fibres.

3.1step 2.1∎

Therefore the zero cocycle gives the split extension.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources