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ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-08-13
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γ(t)=(t,∣t∣) on [−1,1] is rectifiable of length 22 but is not differentiable at 0

Example

The path

γ:[−1,1]→R2,γ(t)=(t,∣t∣),

is rectifiable with length 22, but it is not differentiable at 0 and hence is not C1.

Facts & Assumptions

Verification

technique · computation
1.1

On [−1,0] the derivative is (1,−1), and on [0,1] it is (1,1); each has Euclidean norm 2 by [L3].

givenL1L3
1.2

The right difference quotients at 0 equal (1,1) and the left difference quotients equal (1,−1). They have different limits, so the vector derivative at 0 does not exist.

givenL1
2.1

By [L2], the two pieces have lengths 2 and 2, so the total length is 22.

step 1.1L2
3.1

Thus the path is rectifiable by step 2.1 but not differentiable, and therefore not continuously differentiable, at its corner.

step 2.1step 1.2∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

32 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources