Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Positive coordinate weights define an inner product and change lengths and projections

Example

For positive real weights a0,,an1,

x,ya=k<nakxkyk

is an inner product on Fn, where F=R or C. With weights (1,4) on R2, the vector (1,1) has length 5, and the projection of (1,0) onto span(1,1) is (1/5,1/5) rather than the standard projection (1/2,1/2).

Facts & Assumptions

Given: Positive weights ak and the displayed pairing.

[L1]

A real or complex inner product is linear in the first argument, conjugate symmetric, positive on the diagonal, and definite (Real and complex inner product spaces, with the inner product linear in the first argument).

[L3]

For an orthonormal basis (ei)i<r of a subspace W of a finite-dimensional inner product space, PWv=i<rv,eiei (Orthogonal projection is linear, and an orthonormal basis (ei) of W gives PWv=iv,eiei).

Verification

technique · direct
1.1

Finite-sum algebra gives linearity, conjugate symmetry, and x,xa=kakxk20. Because every ak>0, this sum vanishes exactly when every coordinate of x vanishes, so [L1] holds. For n=0, [L4] leaves only the zero vector.

L1L4algebra
2.1

For weights (1,4), [L2] gives (1,1)a2=1+4=5. Put u=(1,1), v=(1,0) and W=span(u). Then e=ua1u is an orthonormal basis of W, so [L3] gives PWv=v,eae=v,uau,ua1u. Here v,ua=1 and u,ua=5, so PWv=(1/5)u. With both weights 1 the same computation uses v,u=1 and u,u=2 and gives (1/2)u.

L2L3algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 56 results over 17 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.