Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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Weyl integration for SU(2)

Example

Assume the Axiom of Choice. For a continuous class function f on SU(2), SU(2)f(g)dg=12S1f(diag(z,z1))1z22dz, with dz the normalized Haar measure of the circle.

Facts & Assumptions

Given: Assume the Axiom of Choice; SU(2) with its diagonal maximal torus T={diag(z,z1):z=1}, Weyl group of order two, and normalized Haar measures.

[L1]

The diagonal matrices form a maximal torus of SU(2) with Weyl group WS2 of order two acting by zz1 (Maximal tori and Weyl groups of U(n) and SU(n)).

[L2]

Weyl integration: for a class function f on a compact connected G with maximal torus T, Gfdg=W1Tf(t)J(t)dt with J(t)=α>01α(t)12 (Weyl integration formula, Weyl Jacobian).

[L3]

In sl2(C), the adjoint action of t=diag(z,z1) sends E12 to z2E12 and E21 to z2E21, while it fixes the diagonal trace-zero line. Thus the roots of (SU(2),T) are the two characters zz±2, and one may choose α(t)=z2 as the positive root. [algebra]

Verification

technique · direct
1.1

Substituting W=2 into [L2] and using that the class function is constant on Weyl orbits gives SU(2)fdg=12S1f(diag(z,z1))J(diag(z,z1))dz.

L1L2
2.1

By [L3] the single positive root satisfies α(diag(z,z1))=z2, so J(diag(z,z1))=1z22, which is the displayed factor.

L3step 1.1
3.1

As a check, f1 gives 12S11z22dz=12S1(2z2z2)dz=122=1, consistent with the normalization of Haar measure.

step 2.1

Depends on

Used by

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