Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-28
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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FALSE under the Axiom of Choice: AB4 implies AB5

Statement

Assume the Axiom of Choice. Then AB4 implies AB5.

Facts & Assumptions

Given: The Axiom of Choice and the opposite category Abop.

[A1]

The Axiom of Choice (The Axiom of Choice).

[L1]

The category Abop does not satisfy AB5 (The opposite of abelian groups does not satisfy AB5).

[L2]

AB4 is the coproduct-monomorphism axiom (The axioms AB4 and AB4*).

[L3]

Assuming the Axiom of Choice, Ab satisfies AB4* (Assuming the Axiom of Choice, abelian groups satisfy AB4*).

[L4]

The opposite of an abelian category is abelian (The opposite of an abelian category is abelian).

Refutation

1.1L2L3L4algebra

By [L4], the opposite category Abop is abelian. Passing to the opposite exchanges AB4 with AB4*, so [L3] implies that Abop satisfies AB4 in the sense of [L2].

2.1A1L1step 1.1∎

But [L1] shows that Abop does not satisfy AB5. So, even under [A1], AB4 does not imply AB5.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources