Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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FALSE: Baer sum only takes the direct sum of middle objects

Statement

FALSE: Baer sum only takes the direct sum of middle objects

Facts & Assumptions

Given: Two extensions 0→N→Ei→M→0 for i=1,2.

Refutation

technique · direct
1.1givenalgebra

Taking their direct sum gives 0→N⊕N→E1⊕E2→M⊕M→0, whose endpoints are N⊕N and M⊕M, not the required N and M.

2.1step 1.1algebra∎

Pulling this sequence back along Δ:M→M⊕M restores the quotient M, and pushing out along ∇:N⊕N→N restores the subobject N. These two operations, not merely the direct sum of middle terms, define the Baer sum.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources