Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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FALSE: cobounded and cocompact are identical without extra hypotheses

Statement

Cobounded and cocompact are identical without extra hypotheses.

Facts & Assumptions

Given: The trivial action of the trivial group on the open interval (0,1) with its usual metric. Here cocompact means that the orbit space of the action is compact.

[L1]

Coboundedness means that some bounded subset has orbit-union equal to the whole space (Isometric, proper, and cobounded actions on metric spaces).

[L2]

The absolute-value metric makes R a metric space, hence its open interval (0,1) inherits the usual metric (The absolute value makes R a metric space: d(x,y)=xy is a metric, its open balls are the intervals (xr,x+r), and it is unbounded).

Refutation

technique · direct
1.1

The interval (0,1) is bounded, so for the trivial action its single orbit already covers the space. Thus the action is cobounded by [L1].

L1L2
1.2

The orbit space is again (0,1), which is not compact: the open cover Un:=(0,11/n) for n2 covers it, but every finite subfamily misses points sufficiently close to 1. So the action is not cocompact.

L2algebra
2.1

Step 1.1 gives coboundedness while step 1.2 denies cocompactness, refuting the statement.

step 1.1step 1.2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources