Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-generatedPipeline-generatedverified 2026-09-26 (gpt-6-sol)
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Every decision many-one reduction is parsimonious

Statement

Every polynomial-time many-one reduction between decision problems preserves the exact number of witnesses.

Facts & Assumptions

Given: On binary inputs w, let f(w) count the sole witness ε and let g(w) count the two witnesses 0 and 1. These are counting functions with f(w)=1 and g(w)=2 for every w; their associated decision languages, defined by positive count, are both {0,1}∗.

[L1]

A decision many-one reduction need preserve only membership, by Polynomial-time many-one reductions.

[L2]

A parsimonious reduction preserves exact counts, by Parsimonious reductions between counting functions.

Refutation

technique · direct
1.1L1givenconstruct

Let r(w)=w for every binary word w. This is a total linear-time map. The two positive-count decision languages are both {0,1}∗, so r is a many-one reduction between them by [L1].

2.1L2givenstep 1.1

For every w, the source has exactly one accepting witness ε, whereas the target has exactly the two accepting witnesses 0,1. Hence f(w)=1≠2=g(r(w)), so r is not parsimonious under [L2]. Both witness relations are decidable in constant time once their witness is read.

3.1step 1.1step 2.1∎

This one polynomial-time decision reduction refutes the universal claim.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources