How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Every set of reals is Borel
Statement
False assertion: every subset of is Borel.
In ZFC, take an undetermined payoff and the continuous injection supplied below. The set e[A] is a witness that the assertion fails.
Facts & Assumptions
Choice produces an undetermined natural-number game supplies A with neither player winning under AC.
Continuous injections of sequence spaces into the real line gives the continuous injection e in ZF.
Borel hierarchy exhaustion and preservation by continuous pullback makes continuous inverse images of Borel sets Borel in ZFC.
Borel games are determined determines every Borel natural-number payoff in ZFC.
Assume The Axiom of Choice.
Refutation
Given: Work in ZFC throughout this counterexample.
F1 with A1 supplies A and F2 supplies e. Suppose e[A] were Borel in . By continuity of e, F3 with A1 would make Borel in Baire space. This preimage equals A: if e(x)=e(a) for some a in A, injectivity gives x=a; conversely each a in A maps into e[A].
Then F4 with A1 would give a winning strategy for one player for payoff A, contradicting its defining property from F1. Hence e[A] is not Borel and is the required subset of the real line witnessing the failed assertion. QED.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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