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False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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FALSE: every finitely additive nonnegative function on an algebra extends to a measure

Statement

Every finitely additive function from an algebra of subsets to [0,+] that vanishes at the empty set extends to a measure on the generated sigma-algebra.

Facts & Assumptions

Given: The power-set algebra P(N) and the function λ(A)=0 for finite A and λ(A)=+ for infinite A.

[F1]

An algebra of subsets of X is a subfamily of P(X) containing and closed under complements and finite unions. (Algebras of subsets)

[F2]

A measure vanishes at the empty set and is countably additive on every pairwise disjoint sequence in its sigma-algebra, beginning at index 0 and allowing +. (Measures on sigma-algebras)

Refutation

technique · direct
1.1

The function vanishes at . If A and B are disjoint and both finite, their union is finite and 0=0+0; if their union is infinite, at least one of A,B is infinite, so both λ(AB) and λ(A)+λ(B) are +. Thus λ is finitely additive on the algebra [F1].

F1algebra
2.1

The algebra is already the sigma-algebra P(N), so any extension must equal λ there. But the disjoint singleton sequence has union N, while λ(N)=+ and k=0λ({k})=0, contradicting [F2].

step 1.1F2algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources