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FALSE: every finitely additive nonnegative function on an algebra extends to a measure
Statement
Every finitely additive function from an algebra of subsets to that vanishes at the empty set extends to a measure on the generated sigma-algebra.
Facts & Assumptions
Given: The power-set algebra and the function for finite and for infinite .
An algebra of subsets of is a subfamily of containing and closed under complements and finite unions. (Algebras of subsets)
A measure vanishes at the empty set and is countably additive on every pairwise disjoint sequence in its sigma-algebra, beginning at index and allowing . (Measures on sigma-algebras)
Refutation
The function vanishes at . If and are disjoint and both finite, their union is finite and ; if their union is infinite, at least one of is infinite, so both and are . Thus is finitely additive on the algebra [F1].
The algebra is already the sigma-algebra , so any extension must equal there. But the disjoint singleton sequence has union , while and , contradicting [F2].
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- T. Tao, An Introduction to Measure Theory, Section 1.7.2 and Exercise 1.7.6 (standard reference, not scraped)