Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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FALSE: the Galois correspondence preserves inclusion

Statement

False claim. If H1H2 are subgroups in a finite Galois correspondence, then KH1KH2.

Facts & Assumptions

Given: The general inclusion-reversing correspondence of The fundamental theorem of finite Galois theory.

[L1]

The trivial subgroup fixes the whole biquadratic extension, while each order-two subgroup fixes a quadratic field (The complete Galois correspondence for Q(2,3)/Q).

Refutation

technique · direct
1.1

In [L1], the trivial subgroup is strictly contained in an order-two subgroup, but its fixed field is the entire biquadratic field and strictly contains the quadratic fixed field of the larger subgroup.

L1given
2.1

The subgroup containment in step 1.1 produces the reverse strict field containment, so it refutes inclusion preservation.

step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources