Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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FALSE: substituting a fixed matrix A for x defines a ring homomorphism Mn(F[x])Mn(F)

Statement refuted

Refuted claim: For a fixed AMn(F), the coefficientwise rule kCkxkkCkAk is a ring homomorphism Mn(F[x])Mn(F).

This is the invalid substitution step in a familiar pseudo-proof of Cayley-Hamilton; the actual theorem Cayley-Hamilton: every finite-dimensional endomorphism satisfies its characteristic polynomial, χT(T)=0 requires a coefficient-comparison argument.

Facts & Assumptions

Given: Work over any field F and take A=diag(1,0) and B=E12 in M2(F).

[L1]

Matrix multiplication over a commutative ring is defined by finite row-column sums, and the identity matrix has 1 on its diagonal and 0 elsewhere (Entrywise ring-matrix operations, rectangular matrix products, identity matrices and transpose).

Refutation

technique · explicit counterexample
1.1

In M2(F[x]), the row-column formula [L1] and commutativity of F[x] give (xI2)B=B(xI2)=xB.

L1algebra
2.1

The coefficientwise rule has E(xI2)=A, E(B)=B, and E((xI2)B)=E(xB)=BA=0, whereas E(xI2)E(B)=AB=B.

step 1.1givenalgebra
3.1

Since B0, step 2.1 shows E((xI2)B)E(xI2)E(B). The coefficientwise substitution rule is therefore not multiplicative and hence is not a ring homomorphism.

step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 41 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources