Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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FALSE: the local maximum modulus principle needs no connectedness

Statement

Every holomorphic function on an open subset of C whose modulus has an interior local maximum is constant on that open set, even when the open set is disconnected.

Facts & Assumptions

Given: The disjoint open discs D(2,1) and D(2,1) in the complex metric topology (The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement) and their union U.

[L1]

If the modulus of a holomorphic function on a complex domain has an interior local maximum, then the function is constant (Local maximum modulus principle).

Refutation

technique · direct
1.1

The two discs are nonempty, open, and disjoint, so U=D(2,1)D(2,1) is open but disconnected and therefore is not a complex domain (A complex domain is a nonempty connected open subset of C).

given
2.1

Define f=0 on D(2,1) and f=1 on D(2,1). Every point has a neighbourhood on which f is constant, so f is holomorphic on U.

step 1.1algebra
3.1

At every point of the second disc, f=1 is a local maximum, but f is not constant on U because it is 0 on the first disc. Thus the statement is false; the connected-domain hypothesis in [L1] is exactly what prevents this componentwise witness.

step 2.1L1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources