Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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FALSE: if every level set of a real-valued function is measurable, then the function is measurable

Statement

False claim. If every level set {x:f(x)=a} of a real-valued function is measurable, then the function itself is measurable.

Facts & Assumptions

Given: The Axiom of Choice, the Lebesgue measurable-space structure on [0,1], and a Vitali set V[0,1].

[L2]

Assuming the Axiom of Choice, a Vitali set is not Lebesgue measurable. (Assuming the Axiom of Choice, a Vitali set is not Lebesgue measurable)

Refutation

technique · direct
1.1

Define f:[0,1]R by [given, L1] f(x)=x for xV and f(x)=x+2 for xV. Every level set of f is empty, a singleton, or a two-point set, hence measurable.

givenL1
2.1

The set f1([2,3]) is exactly V, because on [0,1]V the [step 1.1, L2] values lie in [0,1] and on V they lie in [2,3]. By [L2], the set V is not measurable, so f is not measurable.

step 1.1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources