Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-09-12
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

FALSE: nondeterministic acceptance requires every branch to halt

Statement

False claim: a nondeterministic Turing machine accepts an input only when every computation branch on that input halts.

Facts & Assumptions

Given: A nondeterministic machine with states q0,qacc,qrej,qL, input alphabet {1}, tape alphabet {1,}, and allowed transitions Δ(q0,1)={(qacc,1,R),(qL,1,L)},Δ(qL,1)={(qL,1,L)}. Take input word w=1.

[A1]

The statement refuted is: nondeterministic acceptance requires every branch on the input to halt.

[L1]

A nondeterministic machine accepts an input when there exists an accepting computation on that input, by Accepting computations of a nondeterministic machine.

Refutation

technique · direct
1.1

One allowed first move from the initial configuration is (qacc,1,R). So there is a one-step computation branch that ends immediately in the accept state.

given
1.2

Another allowed first move is (qL,1,L). From then on the only allowed move is again (qL,1,L), and the left-boundary rule keeps the head at cell 0, so this branch never leaves the nonhalting state qL and therefore does not halt.

given
2.1

By [L1] and step 1.1, the machine accepts w because an accepting computation exists. But step 1.2 gives a branch that does not halt. Therefore [A1] is false.

A1L1step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources