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Second cohomology classifies all nonabelian extensions
Statement refuted
classifies all Lie-algebra extensions, including those with nonabelian kernel.
Facts & Assumptions
Given: A characteristic-zero field and the split extension displayed below.
The classification theorem applies to extensions with abelian kernel, regarded as a module (Second cohomology classifies abelian extensions).
Counterexample
Let be the three-dimensional Heisenberg algebra and take the split extension . Its kernel is nonabelian because it contains basis elements with .
In every extension constructed from a CE -cocycle with coefficient module , the kernel is and its internal bracket is zero. Thus no such construction can be equivalent—by a map fixing the kernel—to the extension in step 1.1. The proof of [L1] uses abelianness both to make the quotient action independent of lifts and to turn Jacobi into the linear equation . Nonabelian kernels require outer-action and nonlinear obstruction data. Hence the word “all” is refuted.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Weibel, Lie Algebra Homology and Cohomology, §§7.6–7.7 (standard reference, not scraped)