Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Injectivity is not part of the enveloping quotient definition

Statement

The canonical map gU(g) is injective merely by the definition of U(g) as a quotient.

Facts & Assumptions

Given: The claim that quotient formation alone proves injectivity.

[L1]

The definition makes the canonical map the composite gT(g)T(g)/I (Universal enveloping algebra).

[L2]

Its injectivity is a PBW corollary (The canonical map g→U(g) is injective).

Refutation

technique · direct dependency check
1.1

From [L1] alone, the kernel of the composite is exactly Ig, with g viewed in tensor degree one. A quotient definition supplies no assertion that this intersection is zero; for comparison, the quotient T(V)/(V) kills its entire degree-one subspace.

L1algebra
2.1

PBW proves that the special enveloping ideal has Ig=0, yielding [L2]. Thus injectivity is true, but it is a theorem using PBW rather than a consequence built into the quotient definition, so the statement as phrased is false.

step 1.1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources