Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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The subspace topology on a leaf is always its manifold topology

Statement

The subspace topology on a leaf is always its manifold topology.

Facts & Assumptions

Given: Use the irrational linear leaf t[(t,αt)]T2 with irrational α.

[A1]

Intrinsically, the leaf is diffeomorphic to R.

Refutation

technique · direct
1.1

As an immersed manifold, the leaf carries the topology transported from [given] R by its parametrization.

given
1.2

If the subspace topology from T2 agreed with that intrinsic [given] topology, the parametrization would be a topological embedding. The leaf would then be an embedded submanifold of the torus.

given
1.3

But the same irrational leaf is dense and not embedded. Therefore its [given] subspace topology cannot equal its manifold topology.

given
2.1

Hence the statement is false. [given] ∎

given

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources